eurovision 1956
Jetty Paerl
Jetty Paerl represented the Netherlands at Eurovision 1956 in Lugano with “De vogels van Holland”; only the winner was announced that year.
- who
- Dutch singer
- born
- 27 May 1921, Amsterdam, Netherlands
- died
- 22 August 2013 (aged 92), Amstelveen, Netherlands
- contest
- 1956
- active
- from 1939
- sang for
- Netherlands
Biography
Jetty Paerl, who died in 2013, was a Dutch singer who had been a member of the resistance. “De vogels van Holland” was the first song performed at the first contest, in Lugano in 1956; the results of that first contest were never published beyond the name of the winner.
Written by ESC Predictions, 8 October 2026. Sources: Wikipedia, “Jetty Paerl”.
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At Eurovision
One song, and what became of it.
-
1956 Lugano
“De vogels van Holland”
Placing not published Only the winner was announced that year. The other placings were never published.
- Sung in
- Dutch
- Written by
- Cor Lemaire, Annie M.G. Schmidt
- Conductor
- Fernando Paggi
- Running order
- 1st of 14
- Age on the night
- 34
- Won that year
- Switzerland: Lys Assia, “Refrain”
The story of Eurovision 1956: Seven countries, fourteen songs, and a result nobody kept
Results as published by the European Broadcasting Union. Biographical details from Wikidata. The photo is from Wikimedia Commons and is credited beside it. Spotted a mistake? Tell us and we'll fix it.